For a puck moves 2.35 m/s in a -22 degree direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50 degree direction the magnitude of the acceleration is mathematically given as
θ=71.4
Generally, the equation for the initial velocity of the puck is mathematically given as
v1=v1cosαi+v1sinαj
v1=(2.35)cos(−22.0)i+(2.35m)sin(−22.0)j
v1=2.1788820582i−0.8803254945j
v2=(6.42)cos(50.0)i+(6.42)sin(50.0)j
v2=4.1266964542i+4.9180053248j
hence,
a=v2−v1/Δt
[tex]a=(4.1266964542i+4.9180053248j) - (2.1788820582i-0.8803254945j)/0.215s[/tex]
a= 9.0596018419i+26.968980555j
In conclusion, the magnitude of acceleration
θ=tan−1(26.968980555/9.0596018419)
θ=71.431423019
θ=71.4
Read more about acceleration
https://brainly.com/question/605631
