Respuesta :

sqdancefan

Answer:

  [tex]X=\left[\begin{array}{cc}-5&2\\0&8\\8&1\end{array}\right][/tex]

Step-by-step explanation:

Solving the given matrix equation, we find ...

  X = (1/4)(C - B)

These operations, subtraction and multiplication by a scalar, are done on a term-by-term basis. A calculator or spreadsheet can do these for you.

For example, the middle right term (row 2, col 2) is ...

  (38 -6)/4 = 32/4 = 8

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Hrishii

Answer:

[tex]X =\begin {bmatrix} -5 & 2\\0 &8\\8 & 1\end{bmatrix}[/tex]

Step-by-step explanation:

[tex] Given \:\: B=\begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix} \: and\: C=\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}[/tex]

To Solve: 4X + B = C

[tex]\implies 4X + \begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix}=\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}[/tex]

[tex]\implies 4X =\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}- \begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix}[/tex]

[tex]\implies 4X =\begin {bmatrix} -12-8 & 6-(-2)\\-1 -(-1)& 38-6\\24-(-8) & -6-(-10)\end{bmatrix}[/tex]

[tex]\implies 4X =\begin {bmatrix} -12-8 & 6+2\\-1 +1 & 38-6\\24+8 & -6+10\end{bmatrix}[/tex]

[tex]\implies 4X =\begin {bmatrix} -20 & 8\\0& 32\\32 & 4\end{bmatrix}[/tex]

[tex]\implies X =\frac{1}{4}\begin {bmatrix} -20 & 8\\0& 32\\32 & 4\end{bmatrix}[/tex]

[tex]\implies X =\begin {bmatrix} \frac{-20}{4} & \frac{8}{4}\\\\\frac{0}{4}& \frac{32}{4}\\\\ \frac{32}{4} & \frac{4}{4}\end{bmatrix}[/tex]

[tex]\implies X =\begin {bmatrix} -5 & 2\\0 &8\\8 & 1\end{bmatrix}[/tex]

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