contestada

A sample of water goes through a temperature change of -74.14 °C while releasing 578.7 joules of heat. The specific heat capacity of water is 4.184 J/(g·°C). What is the mass of this sample? grams (Report your answer using 4 significant figures).

Respuesta :

Ankit

Answer:

[tex] \boxed{ \sf \: m = 1.866 \: grams}[/tex]

Explanation:

Given:

Change in temperature ∆T= -74.14°C

Heat(Energy) released Q= 578.7 joules

Specific heat capacity s = 4.184 J/(g·°C)

To find:

Mass of the sample (m)=?

Solution:

[tex] \sf s= \frac{Q}{m \cdot \Delta T} \\ \sf \: Substituting \: the \: given \: parameters \\ \sf 4.184 = \frac{578.7}{m \times ( - 74.14)} \\ \sf m = \frac{578.7}{4.184 \times ( - 74.14)} \\ \sf m = \frac{578.7}{310.20176} \\ { \sf m = 1.8655 \approx1.866 \: grams}[/tex]

Since, we need the answer in 4 significant figures,

[tex] \boxed{ \sf \: m = 1.866 \: grams}[/tex]

Learn more about specific heat here

brainly.com/question/27365354

Thanks for joining brainly community!

Otras preguntas