let p be a polynomial function where p(x)=x4- dx3 + 8x2 - 10x + 4 if (x-2) is a factor of the polynomial, what is the value of d?

Respuesta :

Answer:

d = 4

Step-by-step explanation:

If (x -2) is a factor of polynomial p(x), then the remainder will be zero.

⇒ p(2) = 0

[tex]\sf \bf 2^4-d*2^3 + 8*2^2 -10*2 + 4 = 0\\\\[/tex]

       16 - 8d + 8*4 - 20 + 4 = 0

        16 - 8d + 32 - 20 + 4 = 0

                   -8d  +  32       = 0

                              -8d      = - 32

                                      d = -32/(-8)

[tex]\boxed{d = 4}[/tex]