The voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.
The voltage of the power source is determined from ohm's law as shown below;
V = IR
where;
But, I = Q/t
V = (Q/t)R
[tex]V = \frac{QR}{t} \\\\V = \frac{(1\times 10^{15} \times 1.602\times 10^{-19} \ C) \times \ 10 \ ohms}{1 \times 60\ s} \\\\V = 2.67 \times 10^{-5} \ V[/tex]
Thus, the voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.
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