Answer: See below
Step-by-step explanation:
Answer (1)
We must break down the expressions into factors. That is:
[tex]\begin{align} \log 12&=\log 4\times 3=\log 2^2\times 3\\ \log 12&=\log 2^2+\log 3=2\log 2+\log 3=2x+y\\ \end{align}[/tex][tex]\log \frac{14}{3}&=\log 14-\log 3 \\ =\log 2\times 7-\log 3\\ \\\log \frac{14}{3}& =\log 2+\log 7-\log 3 \\ =x+z-y\\[/tex]
Answer (2)
[tex]\log 0.3 &=\log \frac{3}{10} \\ \\ =\log 3-\log 10 \\=y-1[/tex]
Answer (3)
[tex]\log 10.5& \\ =\log \frac{21}{2} \\=\log 21-\log 2\\ \\ \log 10.5& \\ =\log 3\times 7-\log 2\\=\log 3+\log 7-\log 2\\=y+z-x[/tex]
