Total surface area of Cuboid:
If [tex]$l$[/tex] be the length of cuboid, [tex]$b$[/tex] be the breadth of cuboid and [tex]$h$[/tex] be the height of cuboid, then its total surface area (TSA) of cuboid is given by,
[tex]\;\longrightarrow\boxed{\tt{TSA = 2(lb + bh + lh)}}[/tex]
A cuboid is also known as rectangular prism.
Elucidation:
We need to find the surface area of the cuboid or rectangular prism whose length, breadth and height are given.
- Length = 6 1/2 = 6.5cm
- Breadth = 2 1/2 = 2.5cm
- Height = 2 2/2 = 2.5cm
Now by using the formula of surface area nd substituting the given values, we get the following results:
[tex]\implies\tt{Surface\;area = 2(6.5 \times 2.5 + 2.5 \times 2.5 + 6.5 \times 2.5)}\\[/tex]
[tex]\implies\tt{Surface\;area = 2(16.25 + 6.25 + 16.25)}\\[/tex]
[tex]\implies\tt{Surface\;area = 2(38.75)}\\[/tex]
[tex]\implies\boxed{\pmb{\tt{Surface\;area = 77.5}}}\\[/tex]
Hence, this is our required solution for this question.
[tex]\rule{300}{1}[/tex]
Additional information:
- Volume of cylinder = πr²h
- T.S.A of cylinder = 2πrh + 2πr²
- Volume of cone = ⅓ πr²h
- C.S.A of cone = πrl
- T.S.A of cone = πrl + πr²
- Volume of cuboid = l * b * h
- C.S.A of cuboid = 2(l + b)h
- T.S.A of cuboid = 2(lb + bh + lh)
- C.S.A of cube = 4a²
- T.S.A of cube = 6a²
- Volume of cube = a³
- Volume of sphere = 4/3πr³
- Surface area of sphere = 4πr²
- Volume of hemisphere = ⅔ πr³
- C.S.A of hemisphere = 2πr²
- T.S.A of hemisphere = 3πr²
