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Segment AB has point A located at (4, 2). If the distance from A to B is 3 units, which of the following could be used to calculate the coordinates for point B? 3 = square root of the quantity of x minus 2 all squared plus y minus 4 all squared 3 = square root of the quantity of x minus 4 all squared plus y minus 2 all squared 3 = square root of the quantity of x plus 2 all squared plus y plus 4 all squared 3 = square root of the quantity of x plus 4 all squared plus y plus 2 all squared

Respuesta :

The equation that can be used to find the coordinates of B given the coordinates of A and the length of the line segment AB is given by: Option B: 3 =√[(x-4)² + (y-2)²]  

What is the distance between two points ( p,q) and (x,y)?

The shortest distance(length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

[tex]D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]

For this case, we're specified that:

The coordinates of A are (4,2)

The distance from A to B = 3

Let the coordinates of B be (x,y), and (p,q) = (4,2), then we get;

[tex]D = \sqrt{(x-p)^2 + (y-q)^2}\\\\or\\\\3 = \sqrt{(x-4)^2 + (y-2)^2}\\[/tex]

Thus, the equation that can be used to find the coordinates of B given the coordinates of A and the length of the line segment AB is given by: Option B: 3 =√[(x-4)² + (y-2)²]  

Learn more about distance between two points here:

brainly.com/question/16410393

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