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A 0.032 g plastic bead hangs from a lightweight thread. Another bead is fixed in position beneath the point where the thread is tied. If both beads have charge q, the moveable bead swings out to the position shown in (Figure 1).

A 0032 g plastic bead hangs from a lightweight thread Another bead is fixed in position beneath the point where the thread is tied If both beads have charge q t class=

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onyebuchinnaji

The magnitude of the charge of the given moveable beads is 9.33 nC.

What is the tension in the string?

The tension in the string is calculated as follows;

Tcos45 = mg

where;

  • T is the tension
  • m is the mass

F = Tsin45

[tex]\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }[/tex]

Magnitude of the charge

[tex]q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC[/tex]

Learn more about charge here: https://brainly.com/question/25922783

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