Find ∠BCD
A)60
B)20
C)80
D)120

Answer:
[tex] \longrightarrow \tt5x + 10 = 3x + 3x[/tex]
[tex] \longrightarrow \tt \: 5x + 10= 6x[/tex]
[tex] \longrightarrow \tt10 = 6x - 5x[/tex]
[tex] \longrightarrow \tt \: 10 = x[/tex]
Replacing value :
✯[tex] \tt m \: \angle \: \: BCD = 5 \times 10 + 10 = \boxed{ \tt{60}} [/tex]
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