What is the surface area of the triangular prism shown?

Answer:
The first step that we are going to do is to solve the area of the top rectangle. We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.
[tex]Area = l * w[/tex]
[tex]Area = 25\ cm * 15\ cm[/tex]
[tex]Area = 375\ cm^2[/tex]
The second side that we are going to solve for is the bottom rectangle. We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.
[tex]Area = l * w[/tex]
[tex]Area = 25\ cm * 12\ cm[/tex]
[tex]Area = 300\ cm^2[/tex]
The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.
[tex]Area = l * w[/tex]
[tex]Area = 25\ cm * 9\ cm[/tex]
[tex]Area = 225\ cm^2[/tex]
The final area that we have to determine are the side triangles. After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles. We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.
[tex]Area = \frac{1}{2}* b*h[/tex]
[tex]Area = \frac{1}{2}* 12\ cm*9\ cm[/tex]
[tex]Area = 54\ cm^2[/tex]
Multiply it by two to get the area for both of the triangles.
[tex]Area = 54\ cm^2 * 2[/tex]
[tex]Area = 108\ cm^2[/tex]
Finally, we are onto the last part which is to add up all of the areas and get the surface area after we combine everything.
[tex]Area_{total}=375\ cm^2 + 300\ cm^2 + 225\ cm^2 + 108\ cm^2[/tex]
[tex]Area_{total}=1008\ cm^2[/tex]
Therefore, our final answer is option B, 1008 [tex]cm^2[/tex]
Hope this helps!