Answer:
a) [tex]-2x^2+5xy[/tex]
b) [tex]-3y^2+5xy[/tex]
Step-by-step explanation:
Part (a)
Given polynomial :[tex]2x^2+3y^2-5xy+1[/tex]
The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:
[tex]-2x^2+5xy[/tex]
[tex](2x^2+3y^2-5xy+1)+(-2x^2+5xy)[/tex]
[tex]=2x^2+3y^2-5xy+1-2x^2+5xy[/tex]
[tex]=2x^2-2x^2+3y^2-5xy+5xy+1[/tex]
[tex]=3y^2+1[/tex]
Part (b)
Given polynomial :[tex]2x^2+3y^2-5xy+1[/tex]
The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:
[tex]-3y^2+5xy[/tex]
[tex](2x^2+3y^2-5xy+1)+(-3y^2+5xy)[/tex]
[tex]=2x^2+3y^2-5xy+1-3y^2+5xy[/tex]
[tex]=2x^2+3y^2-3y^2-5xy+5xy+1[/tex]
[tex]=2x^2+1[/tex]