Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11, 12, 15. There are 10,000 total students. Average GPA: Unknown, Standard Deviation of GPA: 0.02 and it's Normal. a. Find the mean and standard deviation for GPA. (10 points) b. Calculate a 95% confidence interval for the populations mean GPA. (5 points) c. Use Correlation formula to find r between GPA and Age. (10 points) d. Find Regression Line Equation. (5 points)​

Respuesta :

The mean and standard deviation for the GPA of the students will be 3 and 0.8165.

How to calculate the mean?

The mean simply means the average of a given set of numbers. The mean will be:

= 12/4

= 3

The standard deviation will be:

= ✓2/3

= 0.8165

The 95% confidence interval for the populations mean GPA will be 1.70 < U < 4.30. The interval lower limit is:

= 3.00 - 1.299.l

= 1.70

The interval upper limit will be;

= 3.00 + 1.299

= 4.30

Also, the regression line is Y = -1.2857 + 0.3571x.

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