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A battery of emf 20v and internal resistance 1 ohms connected in series with an external resistor4 ohms what is
a power dissipate due to ineternal resistor​

Respuesta :

onyebuchinnaji

The power dissipate due to internal resistor​ is 400 W.

Power dissipated in a circuit

The power dissipate due to internal resistor​ is calculated as follows;

P = IV

P = (V/r)V

P = V²/r

where;

  • V is emf of the battery
  • r is internal resistor

P = (20²)/(1)

P = 400 W

Thus, the power dissipate due to internal resistor​ is 400 W.

Learn more about power dissipated here: https://brainly.com/question/23688821

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