8th grade math . Pythagorran practice

The answers according to rows are:
Mensuration is an aspect of geometry that deals with measurement of volumes and area.
Analysis:
Row 1
Diameter of base = 2 x radius = 2 x 5 = 10
Base area = π[tex]r^{2}[/tex] = π[tex](5)^{2}[/tex] = 25[tex]\pi[/tex]
Volume of cylinder = base area x height = 25π x 7 = 175π
Volume of cone = 1/3 x volume of cylinder = 175π/3
Row 2
Base radius = base diameter/2 = 6/2 = 3
Base area = π[tex]r^{2}[/tex] = π[tex](3)^{2}[/tex] = 9π
Volume of cone = 1/3 x base area x height
base area x height = 3 x volume of cone
base area x height = 3 x 40π
Height = 120π/9π = 40/3
Cylinder volume = 3 x cone volume = 3 x 40π = 120π
Row 3
Base area = π[tex]r^{2}[/tex]
36π = π[tex]r^{2}[/tex]
r2 = [tex]\sqrt{36}[/tex]
r = 6
Base diameter = 2 x 6 = 12
Volume of cone = 1/3 x base area x height
48π = 1/3 x 36π x height
Height = 4
Cylinder volume = 3 x 48 = 144π
In conclusion,
ROW 1 : diameter of base = 10, base area = 25π, volume of cylinder = 175π
volume of cone = [tex]\frac{175}{3}[/tex]π
ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π
ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π
Learn more about mensuration: brainly.com/question/18541562
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