If the radius of the semi-circle is 38 m. Then the area of the training field will be 11,908.459 square meters.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 97 m long and 76 m wide.
Then the radius of the semi-circle will be
2r = 76
r = 38 m
Then the area of the training field will be
Area = area of rectangle + 2 x area of semi-circle
Area = 97 x 76 + 2 x (1/2) x π x 38²
Area = 7372 + 4536.459
Area = 11908.459 square m
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