The true statement concerning ABC is: the angle B is the largest angle - option B.
Law of Cosines
This law is represented by the equation: C²=A²+B²-2ABcosθ, where: A,B and C are the sides of a triangle and θ=angle.
For solving this question, you should apply the Law of Cosines, where:
AB=11
BC=11
AC=14
BC²=AB²+AC²-2*AB*AC*cos A
11²=11²+14²-2*11*14*cos A
121=121+196-308cosA
308cosA=196+121-121
308cosA=196
cosA=196/308=7/11
arccos (7/11)=50.48°
A=50.48°
AC²=AB²+BC²-2*AB*BC*cos B
14²=11²+11²-2*11*11*cos B
196=121+121-242cosB
242cosB=-196+121+121
242cosB=46
cosB=46/242=23/11
arccos (23/11)=79.04°
B=79.04°
AB²=BC²+AC²-2*BC*AC*cos C
11²=11²+14²-2*11*14*cos C
121=121+196-308cosC
308cosC=196+121-121
308cosC=196
cosC=196/308=7/11
arccos (7/11)=50.48°
C=50.48°
Then,B > A and C
Read more about the Law of Cosines here:
brainly.com/question/8288607
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