The proton will be moving if it is to follow a circular path with radius 2cm in magnetic field of 0.7T is 1.34 x 10⁷ m/s.
What is magnetic field?
It is the region of space where a charge experiences the magnetic force when it enters the field.
While moving in the circular path, centripetal force is equal to the magnetic force.
Fm = Fc
q x v x B = m x v² / r
v= qBr /m
where mass of proton m =1.67262 × 10−27 kg, charge of proton q =1.6 x 10⁻¹⁹ C and magnetic field B =0.7T.
Then, velocity is
v = 1.6 x 10⁻¹⁹ x 0.7 x 0.02 / 1.67262 × 10⁻²⁷
v = 1.34 x 10⁷ m/s.
Thus, the proton will be moving if it is to follow a circular path with radius 2cm in magnetic field of 0.7T is 1.34 x 10⁷ m/s.
Learn more about magnetic field.
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