Answer: C. [tex]4\sqrt{2}[/tex] units.
Step-by-step explanation:
From the given figure , a square is shown with diagonal 8 units.
To find : the length of side (s) of the square .
In a square : All four sides are equal in length and all four angles are right angles.
Thus, The diagonal(hypotenuse) is making two right -angled triangle with the sides of square.
So by Pythagoras theorem of right triangles , we have
[tex]8^2=s^2+s^2[/tex]
[tex]64=2s^2[/tex]
[tex]s^2=\frac{64}{2}=32[/tex]
⇒ [tex]s=\sqrt{32} =\sqrt{16*2} =4\sqrt{2}[/tex]
Hence, the length of side s of the square = [tex]4\sqrt{2}[/tex] units.
