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At constant temperature, if the volume of the gas decreased to the given value, the pressure increases to 2.16atm.

What is Boyle's law?

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

  • Initial volume of the gas V₁ = 682mL = 0.682L
  • Initial pressure of the gas P₁ = 1.33atm
  • Final volume of the gas V₂ = 0.419L
  • Final pressure of the gas P₂ = ?

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.33atm × 0.682L) / 0.419L

P₂ = 0.90706Latm / 0.419L

P₂ = 2.16atm

Therefore, at constant temperature, if the volume of the gas decreased to the given value, the pressure increases to 2.16atm.

Learn more about Boyle's law here: brainly.com/question/1437490

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