A gas at STP is heated to 35 degree C. The new pressure will be 2.41 atm.
What is Gay-Lussac law?
The pressure of the mass of the gas is directly proportional; to the temperature of the gas.
[tex]\dfrac{P_1 }{T_1} =\dfrac{P_2}{T_2}[/tex]
Converting the temperature into kelvin
The initial temperature = 35 °C = 35 + 273 K= 308 K
The final temperature = 50 °C =50 + 273 K = 323 K
Initial pressure = 2.3 atm
Final pressure ?
Putting the values in the equation
[tex]\dfrac{P_1 }{T_1} =\dfrac{P_2}{T_2}\\\\\\{P_2 = \dfrac{P_1 \times T_2}{T_1} \\\\\\\\\\{P_2 = \dfrac{2.3 \times 323 }{308} = 2.41 atm.[/tex]
Thus, the new pressure will be 2.41 atm.
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