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How much ribbon would be needed to go around a package that had a length 2x^2+3x-5/x^2+x-3 centimeters and width x^2-x-5/x^2+x-3 centimeters?

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Answer:

23cm

Step-by-step explanation:

If you multiply like terms you will get the answers. Then you add last to get 23cm

The required length ribbon needed to go around the package is 2(3x^2 + 2x -10) / (x^2 + x - 3).

Given that,
Package that had a length of 2x^2+3x-5/x^2+x-3 centimeters and width x^2-x-5/x^2+x-3.

How much ribbon would be needed to go around the package in centimeters is to be determined.

What is the perimeter?

Perimeter is the measure of the figure on its circumference.

What is a rectangle?

The rectangle is a four-sided polygon whose opposites sides are equal and has an angle of 90° between its sides.

Quantity of ribbon = perimeter of the rectangular package
                            = 2 * length + 2* width
                            = 2 * (2x^2+3x-5/x^2+x-3) + 2(x^2-x-5/x^2+x-3)
                            = 2 (3x^2 + 2x -10) / (x^2 + x - 3)

Thus, the required length of  ribbon needed to go around the package is 2(3x^2 + 2x -10) / (x^2 + x - 3).

Learn more about perimeter here:

brainly.com/question/6465134

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