The mass of butane gas that can be held in a 3.00 l container at STP is 0.0022g.
The ideal gas law says that the particles of the gas do not repel each other or attract.
Given that, Volume of the gas V = 3.00 L
STP; P = 1.0atm, T = 273.15K
The mass ?
R is the ideal gas constant ( 0.08206 Latm/molK )
[tex]PV = nRT\\\\n = \dfrac{PV }{ RT} \\\\n = \dfrac{ 1.0atm \times 3.00L }{ 0.08206 Latm/molK \times 273.15K}\\\\n = \dfrac{3.00Latm }{ 22.41 Latm/mol}\\n = 0.13mol[/tex]
Now, calculate the mass,
The molar mass of butane is 58.12 g
Mass = 0.13mol × 58.12 g/mol
Mass = 0.0022g
Thus, the mass of butane gas that can be held in a 3.00 l container at STP is 0.0022g.
Learn more about Ideal Gas Law
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