Plot a graph showing the variation of stopping potential with the frequency of incident radiation for two different photosensitive materials having work Functions [tex]{\omega{1}}[/tex] and [tex]{\omega{2}}[/tex] [tex]{(\omega{1}>\omega{2})}[/tex]. On what factors does the (i) Slope and (ii) intercept of the lines depends?​

Respuesta :

We know By Einstein's Photoelectric Equation:

[tex]{:\implies \quad \sf h\nu =h\nu_{0}+\dfrac{1}{2}m{v^{2}}_{max}}[/tex]

[tex]{:\implies \quad \sf h\nu =h\nu_{0}+eV_{0}}[/tex]

[tex]{:\implies \quad \sf eV_{0}=h\nu -h\nu_{0}}[/tex]

[tex]{:\implies \quad \sf V_{0}=\dfrac{h\nu}{e}-\dfrac{h\nu_{0}}{e}}[/tex]

Since [tex]{\nu}[/tex] is plotted along X-axis and [tex]{V_0}[/tex] along Y-axis, it represents a straight line

(i) The slope of [tex]{V_{0}}[/tex] versus [tex]{\nu}[/tex] graph= (h/e) i.e it is a constant quantity and does not depend on the nature of the metal surface

(ii) The intercept on the [tex]{\nu}[/tex]-axis = [tex]{(h\nu_{0}/e)}[/tex] i.e it depends on the work function of the metal surface

Refer to the attachment for the graph

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