[tex]{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}[/tex]
0.72 liters
Explanation:
[tex] \sf Volume \: before \: heated(V_1) = 0.5l \\ \\ \sf Temperture \: before \: heated(T_1) = 20{ \degree} C = 20 + 273.15 = 293.15K \\ \\ \sf Volume \: after \: heated(V_2) = ? \\ \\ \sf Temperature \: after \: heated(T_2) = 150{ \degree}C = 150 + 273.15 = 423.15K[/tex]
[tex] \textsf{By using Charles's law} \\ \\ \tt{ \frac{V_1}{T_1} = \frac{V_2}{T_2} }[/tex]
[tex] \sf Now \: sustituting \: the \: values[/tex]
[tex] \sf \longmapsto \frac{0.5}{293.15} = \frac{V_2}{423.15} \\ \\ \\ \sf \longmapsto \frac{0.5 \times 423.15}{293.15} = V_2 \\ \\ \\ \sf \longmapsto \frac{211.575}{293.15} = V_2 \\ \\ \\ \boxed {\longmapsto 0.72l = V_2}[/tex]
