Answer:
[tex]4(x-5)(3{x}^{2}+1)[/tex]
Step-by-step explanation:
1) Find the Greatest Common Factor (GCF).
1 - What is the largest number that divides evenly into [tex]12x^3,-60x^2,4x,[/tex] and [tex]-20[/tex] ?
It is [tex]4.[/tex]
2 - What is the highest degree of [tex]x[/tex] that divides evenly into [tex]12x^3,-60x^2,4x,[/tex] and [tex]-20[/tex] ?
It is 1, since [tex]x[/tex] is not in every term.
3 - Multiplying the results above,
The GCF is 4.
2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
[tex]4(\frac{12{x}^{3}}{4}+\frac{-60{x}^{2}}{4}+\frac{4x}{4}-\frac{20}{4})[/tex]
3) Simplify each term in parentheses.
[tex]4(3{x}^{3}-15{x}^{2}+x-5)[/tex]
4) Factor out common terms in the first two terms, then in the last two terms.
[tex]4(3{x}^{2}(x-5)+(x-5))[/tex]
5) Factor out the common term [tex]x-5[/tex].
[tex]4(x-5)(3{x}^{2}+1)[/tex]
