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A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the car?

Respuesta :

Acceleration

  • a=v-u/t
  • a=20-0)6.6
  • a=20/6.6
  • a=3.03m/s²

Now

Apply Newtons second law

  • F=ma
  • F=1000(3.03)
  • F=3030N

To find frictional force we need coefficient of friction which is not given .

generally for car case the value of coefficient is 0.6-0.8 .

Putting max 0.8

  • f=$\mu$ N
  • f=0.8(3030)
  • f=2424N

Note:

Last part is assumption not accurate

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