Respuesta :
The rank of the bulbs based on their brightness are C>A=B>D=E
What is power?
The power across any resistor is equal to the square of current through that resistor and resistance. The power defines the brightness of the bulb.
The equivalent resistance of A and B bulb R(AB) = Rx R/R+R = R/2
The equivalent resistance of bulb C, D and E, R(CDE) = R x (R+R)/ R+R+R =2R/3
Power through bub A= P(A) = I(A)² R(A) = V²/R
As, bulb A and B has same resistance, P(A )=P(B) =V²/R.............(1)
Power through bulb C, P(C) = (2/3 x I(CDE)) x R = (2/3 x (3V/2R)² x R = 3/2 x V²/R..............(2)
Power through D and E bulb are equal, P(D) =P (E) = (1/3 x I(CDE)) x R = (2/3 x (3V/2R)² x R = 3/4 x V²/R.............(3)
Comparing equation (1), (2) and (3), the brightness of the bulbs are ranked as
P(C) > P(A) = P(B) > P(D) = P(E)
Thus, the rank of the bulbs based on their brightness are C>A=B>D=E
Learn more about power.
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