An electron is in a finite square well that is 8 ev deep and 0. 5 nm wide. (a) solve numerically for the energy of the ground state and the first excited state of this system

Respuesta :

The energy of the ground state and the first excited state of this system will be 0.014 eV and 0.059 eV, respectively.

What is energy level?

When a subatomic particles system or particle is bound, it can only take on discrete energy values known as energy levels.

The energy level for the nth orbit is found as;

[tex]\rm E_n= \frac{n^2 \pi^2 h^2}{2m_ea^2}\\\\\ E_n=n^2(\frac{\pi^2 (197 \ Mev)^2}{2 \times 0.511 \ Mev \times 5 \ nm} )\\\\ E_n= n^2 (0.014 \ eV)[/tex]

For ground state,n=1,

E_1 =0.014 eV

For first excited state,n=2,

E₂=4 ×0.014

E₂=0.059 eV

Hence,the energy of the ground state and the first excited state of this system will be 0.014 eV and 0.059 eV, respectively.

To learn more about the energy level, refer:

https://brainly.com/question/17396431

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