The percentage of the iceberg that is visible above the water's surface will be 11.5%.
Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
The mass and density relation is given as
mass = density × volume
Density of ice = 917 kg/m³
Density of the seawater=1025 kg/m³
The ratio by which the iceberg submerge is found as;
[tex]\rm \frac{V_S}{V} =\frac{\rho}{\rho_0} \\\\ \frac{V_S}{V} =\frac{917}{1025} \\\\ \frac{V_S}{V} =.895[/tex]
Hence,89.5 % of the ice is submerged.
The percentage of the iceberg that is visible above the water's surface is;
⇒1-.89.5 %
⇒11.55 %
Hence, the percentage of the iceberg that is visible above the water's surface will be 11.5%.
To learn more about the density refers to the link;
brainly.com/question/952755
