Respuesta :
The Entropy change will be 204.97 J/K.
What is Entropy ?
The entropy of an object is a measure of the amount of energy which is unavailable to do work.
Entropy is also a measure of the number of possible arrangements the atoms in a system can have.
In this sense, entropy is a measure of uncertainty or randomness.
[tex]\rm dS = Rn\; ln \dfrac{V_{1}}{V_{2}}[/tex]
From ideal gas equation it is known that: pV=nRT
nR=pV/T
Firstly, let's write the given values:
Since, it's an ideal gas therefore;
P=1 bar
T=298 K
For CO₂= [tex]\rm V_{CO_{2}} = 0.7 m^{3}[/tex]
For N₂= [tex]\rm V_{N_{2}} = 0.3 m^{3}[/tex]
Thus, the final volume will be V₂= 0.7 +0.3 = 1 m3
- For CO₂,
∴ nR=pV/T
[tex]\rm nR = \dfrac{0.7\times 10^{5} }{298} = 234.89[/tex]
So, entropy change for CO₂ will be:
[tex]\rm dS_{CO_{2}} = 234.89\; ln \dfrac{1}{0.7} = 83.77 \;J/K[/tex]
- For N₂,
[tex]\rm nR = \dfrac{0.3\times 10^{5} }{298} = 100.67[/tex]
So, entropy change for N₂ will be:
[tex]\rm dS_{N_{2}} =100.67\; ln \dfrac{1}{0.3} = 121.20 \;J/K[/tex]
Now, total entropy change can be calculated as:
[tex]\rm dS_{Total} = \rm dS_{CO_{2}}+ \rm dS_{N_{2}}[/tex]
= 83.77 +121.20
=204.97 J/K
Thus, entropy change will be 204.97 J/K.
To know more about Entropy
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