The equation of circle whose center (3, -15) and radius 3 units is [tex](x-3)^{2} +(y+15)^{2} = 9[/tex].
What is the Equation of Circle?
The standard equation of a circle is given by:[tex](x-h)^2 + (y-k)^2 = r^2[/tex] Where (h, k) is the coordinates of center of the circle and r is the radius.
Here, center of circle is (3, -15)
and radius of circle is 3 units
Then, Equation of circle
⇒ [tex](x-h)^2 + (y-k)^2 = r^2[/tex]
[tex](x-3)^2 + (y-(-15))^2 = 3^2[/tex]
[tex](x-3)^2 + (y+15)^2 = 9[/tex]
Thus, the equation of circle whose center (3, -15) and radius 3 units is [tex](x-3)^{2} +(y+15)^{2} = 9[/tex].
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