The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.
Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.
If the given turbine is assumed to be reversible;
[tex]\rm P_I[/tex](Initial pressure)=60 mpa = 60 bar
[tex]\rm T_i[/tex](Initial temperature)=600° C
[tex]\rm P_e[/tex] (Exit pressure)=600 kpa=6 bar
The heat balance equation is;
[tex]\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e[/tex]
The change in the entropy is;
[tex]\rm S_2-S_1=\frac{\delta q}{dt}[/tex]
The work done by the turbine is;
[tex]\rm W_t = h_i-h_e\\\\ W_t =3658.4 -29.5019\\\\ W_t =708.2 \ kJ/kg[/tex]
Hence,the work done by the turbine will be 708.2 kJ/kg.
To learn more about the temperature, refer to the link;
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