Respuesta :
a) The velocity of the 3 kg ball after the collision will be 19.33 m/sec.
b) The kinetic energy before and after the collision IS 294 and 560 J.
c)The collision is elastic in nature.
What is the law of conservation of momentum?
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
a)
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
[tex]\rm m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\\\\ 8 \times 4 +3 \times 14 = 8 \times 2 + 3 \times v_2 \\\\ v_2 = 19.33 \ m/sec[/tex]
b)
The kinetic energy before the collision is:
[tex]\rm KE_1 = \frac{1}{2} mu_1^2 \\\\ \rm KE_1 = \frac{1}{2} \times 3 \times 14 ^2 \\\\ KE_1=294 \ J[/tex]
The kinetic energy after the collision is:
[tex]\rm KE_2 = \frac{1}{2} mv_2^2 \\\\ \rm KE_1 = \frac{1}{2} \times 3 \times (19.33) ^2 \\\\ KE_2=560.47 \ J[/tex]
c)
This is an elastic collision because the kinetic energy before the collision is equal to the kinetic energy after the impact.
Hence, the velocity of the 3 kg ball after the collision will be 19.33 m/sec and the collision is elastic in nature.
To learn more about the law of conservation of momentum refer;
https://brainly.com/question/1113396
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