The force on each charge will be 5 N. The electric force in case 2 is obtaining the value from case 1.
The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The electric force is found as;
[tex]\rm 20 = \frac{Kq^2}{1^2} \\\\ Kq^2=20[/tex]
The force on each charge in case 2 is found as;
[tex]\rm F= \frac{20}{2^2} \\\\ F= \frac{20}{4} \\\\ F= 5 \ N[/tex]
Hence, the force on each charge will be 5 N.
To learn more about Columb's law refer to the link;
brainly.com/question/1616890
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