1. 2×10−5molA 1. 2×10−5mol sample of ca(oh)2 is dissolved in water. The pH o steh sample is
pH is potential hydrogen. It is the measurement of the acidity and basicity of any solution.
The ca(oh)2 sample is 1. 2×10−5 mol.
To calculate the pH, the formula is pH = -log[H3O+]
First, calculate the molarity of ca(oh)2 is 4.8 x 10-5M
[OH-] = 9.6 x 10-5M
[OH-][H3O+] = kw (1.0 x 10-14)
[H3O+] = kw / [OH-]
[H3O+] = 1.0 x 10-14 / 9.6 x 10-5
[H3O+]= 1.04 x 10-10M
pH= -log[1.04 x 10-10M]
pH= 9.98
Thus, the pH is 9.98
Learn more about pH
https://brainly.com/question/15289741
#SPJ4