Water at 712 k and 44 mpa has a compressibility factor, z » 0. 38. Estimate the temperature and pressure at which methane will have a similar z, using the 2 parameter principle of corresponding states

Respuesta :

The temperature and pressure at which methane will have a similar z IS 173.22 K and 91.75 bar.

What is compressibility  factor ?

The compressibility factor (Z) is a useful thermodynamic property for modifying the ideal gas law to account for behavior of real gases.

It is a measure of how much the thermodynamic properties of a real gas deviate from those expected of an ideal gas.

For water ,

[tex]\rm T_{c} = 647.1K\\P_{c} = 220.55 bar[/tex]

For methane

[tex]\rm T_{c} = 190.6K\\P_{c} = 45.99 bar[/tex]

Given water at 712 K & 44MPa

= 712 K & 440 bar and  z » 0. 38

[tex]\rm T_{r} = \dfrac{T}{ T_{c} } \\\\\\\dfrac {647.1}{712}= 0.9088\\\\\rm P_{r} = \dfrac{P}{ P_{c} }\\\\\\\dfrac {440}{220.55}= 1.995\\\\[/tex]

Using principle of corresponding states, for methane

z » 0. 38

[tex]\rm T_{r} = 0.9088\\\\ P_{r} = 1.995\\[/tex]

[tex]\rm T = T_{r} T_{c} = 0.9088 \times 190.6 = 173.217\; K\\P = P_{r} P_{c} = 1.995\times 95.99 = 91.75\;bar[/tex]

The temperature and pressure at which methane will have a similar z IS 173.22 K and 91.75 bar.

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