Voltage across the wire will be 0.072 V. Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
Given data;
ρ(resistivity)=1. 72 × 10^-8 ωm
L(length of wire)=1. 0 m
A (cross-sectional area =2. 0 × 10^-6 m²
Current(I)= 0. 20 A
Voltage(V)=?
This current-voltage connection may be expressed mathematically as,
The Equation of Ohm's Law;
[tex]\rm V=IR \\\\ V=I(\frac{\rho L}{A} )\\\\ V=0.20 \times \frac{72 \times 10^{-8}\times 1.0}{2 \times 10^{-6}}\\\\ V=0.072 \ V[/tex]
Hence,voltage across the wire will be 0.072 V.
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