The area enclosed by the curves y=x³-8x² 18x-5 and y=x + 5 is 71/6 or 11.83 square units.
It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.
We have two curves:
y=x³-8x² 18x-5 and
y=x + 5
The intersection point will be:
(1, 6), (2, 7), and (5, 10)
From the graph, we can integrate to evaluate the area enclosed by the curves:
[tex]=\rm \int\limits^2_1 {[(x^3-8x^2+18x- 5)-(x+5)]} \, dx + \int\limits^5_2 {[(x+5)-(x^3-8x^2+18x- 5)]} \, dx[/tex]
After calculating, we get:
Area = 142/12 = 71/6 or 11.83 square units
Thus, the area enclosed by the curves y=x³-8x² 18x-5 and y=x + 5 is 71/6 or 11.83 square units.
Learn more about integration here:
brainly.com/question/18125359
#SPJ4
