Please help me with this

Answer:
Find the hypotenuse of the triangle, and that will help a lot!
Step-by-step explanation:
Pythagorean Theorem: a^2 + b^2 = c^2 (Where c is the hypotenuse)
Here we have two leg lengths, 3 and 8.
We can put it in the formula, where it would look something like this:
3^2 + 8^2 = c^2
After simplifying, you would get that c = [tex]\sqrt{73}[/tex]
Now for the trig functions:
your adjacent leg would be 8, opposite leg would be 3, and hypotenuse [tex]\sqrt{73}[/tex]
cos θ = adj/hyp (your θ should be on the bottom left i think)
cos = 8/[tex]\sqrt{73}[/tex]
sin = 7/[tex]\sqrt{73}[/tex]
tan = 3/8
sec = [tex]\sqrt{73}[/tex]/8
csc = [tex]\sqrt{73}[/tex]/3
I don't know what the sixth one would be, but those are the five main ones.