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A gas is found with an unknown volume at a pressure of 1.5 atm and a temperature of 325K If the pressure is raised to 1.2 atm, the temperature is decreased to , 320K and the final volume is measured to 48 liters, what was the initial volume of the gas? 110 L 121 39 T. 42 L

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Given the change in the pressure and temperature of the gas, the initial volume of the gas is 39 Liters.

Option C)39L is the correct answer.

What is Combined gas law?

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = ?
  • Initial pressure P₁ = 1.5atm
  • Initial temperature T₁ = 325K
  • Final volume V₂ = 48L
  • Final pressure P₂ = 1.2atm
  • Final temperature T₂ = 320K

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

V₁ = P₂V₂T₁ / P₁T₂

V₁ = ( 1.2atm × 48L × 325K ) / ( 1.5atm × 320K )

V₁ = 18720LatmK / 480atmK

V₁ = 18720LatmK / 480atmK

V₁ = 39L

Given the change in the pressure and temperature of the gas, the initial volume of the gas is 39 Liters.

Option C)39L is the correct answer.

Learn more about the combined gas law here: brainly.com/question/25944795

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