A student increases the temperature of a 300 cm^3 balloon from 300 K to 600 K. what will the new volume of the ballon be​

Respuesta :

Answer:

600 cm^3

Explanation:

V1/T1 = V2/T2    

300/300 = V2 * 600

V2 = 600 cm^3

This is an exercise in the law of Jackes Alejandro Charles.

To start solving this exercise, we obtain the following data:

Data:

  • V₁ = 300 cm³
  • T₁ = 300 k
  • V₂ = ¿?
  • T₂ = 600 km

If the temperature doubles the volume doubles; If the temperature is halved, the volume is halved.

"Mathematically this law expresses itself"

[tex]\bf{\dfrac{V_{1}}{T_{1}}=\dfrac{V_{2}}{T_{2}} \qquad \ in \ where: }[/tex]

  • V₁= Initial volume
  • V₂ = Final volume
  • T₁ = Initial temperature
  • T₂ = Final temperature

We can also express it: V₁T₂=V₂T₁

Clear for "V₂":

[tex]\bf{V_{2}=\dfrac{V_{1}T_{2}}{T_{1}} \ \ \to \ \ \ Clear \ formula }[/tex]

We clear our data in the formula:

[tex]\bf{V_{2}=\dfrac{(300 \ cm^{3})(600 \not{k}) }{300 \not{K}} }[/tex]

[tex]\bf{V_{2}=600 \ cm^{3} }[/tex]

The new volume of the balloon will be 600 cm³.

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