The volume of the hydrogen gas at the quoted temperature and pressure would be 0.21 Liters
Gas law
1 mole of gas at stp = 1 L
Hence, 0.24 mole at stp = 0.24 x 1 = 0.24 L
Using the gas law: p1v1/p2v2 = t1/t2
In this case p1 = 760, v1 = 0.24, t1 = 273, p2 = 988, and t2 = 318
Thus:
v2 = p1v1t2/p2t1 = 760 x 0.24 x 318/988 x 273 = 0.21 L
The volume would be 0.21 Liters
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