Answer:
[tex]\huge\boxed{\bf\:2\left(3x-1\right)\left(3x+2\right) }[/tex]
Step-by-step explanation:
[tex]18x^{2} + 6x - 4\\\\Factor \: out \: the \: common \: factor = 2\\\\= 2\left(9x^{2}+3x-2\right) \\\\Split\:the\:quadraric\:equation\:inside\:the\:parentheses \\\:using\:the\:splitting-the-middle-term \:method.\\\\= 2\left(9x^{2}-3x\right)+\left(6x-2\right) \\= 2 (3x\left(3x-1\right)+2\left(3x-1\right) )\\= \boxed{\bf\:2 \left(3x-1\right)\left(3x+2\right) }[/tex]
[tex]\rule{150pt}{2pt}[/tex]
Answer:
2(3x - 1)(3x + 2)
Step-by-step explanation:
18x² + 6x - 4 ← factor out 2 from each term
= 2(9x² + 3x - 2) ← factor the quadratic
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 9 × - 2 = - 18 and sum = + 3
the factors are - 3 and + 6
use these factors to split the x- term
9x² - 3x + 6x - 2 ( factor first/second and third/fourth terms )
= 3x(3x - 1) + 2(3x - 1) ← factor out (3x - 1) from each term
= (3x - 1)(3x + 2) ← in factored form
then
18x² + 6x - 4
= 2(3x - 1)(3x + 2)
