One end of a 3.40 m long plane is raised a height of 2.00 m. A 6.00 kg block slides down the plane reaching a speed of 5.40 m/s at the bottom. Find the work done by friction.

Respuesta :

The work done by friction will be -30.1 Negative shows the work done by the friction.

What is work done?

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive, and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force, it will be positive.

Work done by all the forces =Change in the kinetic energy

Potential energy+Work done by friction=KE₂-KE₁

[tex]\rm mgh+W_X==\frac{1}{2} m(V_B^2-Va^2)\\\\W_{friction}=\frac{1}{2} \times 6 \times (5.40)^2-6\times 9.8 \times 2 \\\\ W_{friction}=-30.1 \ J[/tex]

Hence,the work done by friction will be -30.1 J

To learn more about the work done, refer to the link ;

https://brainly.com/question/3902440

#SPJ1