lillypoteete14
contestada

A 3.00-liter sample of gas is at 288 K and 1.00 atm. What's the temperature of the sample if the pressure is increased to 2.00 atm, and its volume is decreased to 1.50 liters?

Respuesta :

Answer:

288 K

Explanation:

Formula to be used :

P₁V₁/T₁ = P₂V₂/T₂

Given :

  1. P₁ = 1 atm
  2. V₁ = 3 L
  3. T₁ = 288 K
  4. P₂ = 2 atm
  5. V₂ = 1.5 L

Solving :

  • T₂ = P₂V₂T₁ / P₁V₁
  • T₂ = 2 x 1.5 x 288 / 1 x 3
  • T₂ = 3 x 288 / 3
  • T₂ = 288 K

Otras preguntas