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Given: NQ¯¯¯¯¯¯ is an altitude of △MNP.

Prove: sinMm=sinPp
Triangle M N P with point Q between points M and P. A segment extends from point N to point Q creating right angle N Q P. Segment M N is labeled lowercase p. Segment N P is labeled lowercase m. Segment N Q is labeled lowercase h.



Drag and drop a statement or reason to each box to correctly complete the proof.

Statement Reason
NQ¯¯¯¯¯¯ is an altitude of △MNP. Given
∠NQM and ∠NQP are right angles. Response area
â–³NQM and â–³NQP are right triangles. Definition of right triangle
sinM=hp and sinP=hm Definition of sine ratio
Response area Multiplication Property of Equality
psinM=msinP Response area
Response area Division Property of Equality
sinMm=sinPp Simplify.

Given NQ is an altitude of MNP Prove sinMmsinPp Triangle M N P with point Q between points M and P A segment extends from point N to point Q creating right angl class=

Respuesta :

Martebi

The Prove of sinMm=sinPp are:

  • Definition of a right triangle.
  • Sin M = h/p and sin P h/m.
  • Substitution property of equality.
  • Division property of Equality.

What is right triangle?

A triangle that is known to have only one of its interior angles to be 90° is known to be a right triangle.

Note that  sinMm=sinPp is said to be a right triangle as it has its longest side to be the right triangle and it follows the Substitution property of equality and Division property of Equality.

Learn more about triangle from

https://brainly.com/question/17335144

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