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A car and an SUV both hit a patch of ice while
driving eastbound down the road. The 1200-kg
car was moving at 5 m/s when the 2600-kg
SUV hit it from behind at a speed of 12 m/s.
Upon impact, the car veers off the side of the
road at a speed of 10 m/s. The SUV continues
forward at its new velocity. Calculate the final
speed of the SUV

Respuesta :

The final speed of the SUV will be 21.69 m/sec. Apply law of conservation of momentum principle in given problem.

What is the law of conservation of linear momentum?

According to the law of conservation of linear momentum before the collision is equal to the momentum after the collision. These laws state that about how momentum gets conserved.

Apply law of conservation of momentum principle;

m₁v₁+m₂u₂=m₁v₁+m₂v₂

1200-kg × 5 m/s+ 2600-kg× 12 m/s.=1200-kg ×10+2600-kg×V

6000+31200=12000+2600 ×V

V=21.69 m/sec

Hence,the final speed of the SUV will be 21.69 m/sec.

To learn more about the law of conservation of momentum, refer;

https://brainly.com/question/17140635

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