The mass of Cl₂ required to react completely with 10.0 g of Na given the data is 15.4 g
Na + ½Cl₂ —> NaCl
From the balanced equation above,
23 g of Na required 35.5 g of Cl₂
From the balanced equation above,
23 g of Na required 35.5 g of Cl₂
Therefore,
10 g of Na will require = (10 × 35.5) / 23 = 15.4 g of Cl₂
Thus, 15.4 g of Cl₂ are required for the reaction
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