The limiting reactant is hydrogen. The mass of water produced is 18.02g.
What is limiting reactant?
The limiting reactant in a chemical reaction determines the amount of product formed.
Balance equation is: 2H₂(g) + 1O₂(g) → 2H₂O(l)
Find the moles for each of the reactants, n = m/M
n(H₂) = 4.04g / 2.02 g/mol= 2.00mol
n(O2) = 16.00g / 32.00 g/mol = 0.05mol
Molar mass of water is (2 x 1.01) + (16) = 18.02 g/mol
The ratio is 1:2 ,i.e. one mole of O₂ will produce twice as many moles of water. Therefore, multiply the amount of moles for O₂ by two
n (O₂) = 0.05mol * 2 = 1mol
The mass of water produced,
m(H2O) = 1mol * 18.02g/mol = 18.02g
Thus, 18.02g is the mass of water produced.
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